Find the value of ∫2x cos (x2 – 5).

Solution: Let, I = ∫2xcos(x2 – 5).dx
Let x2 – 5 = t …..(1)
2x.dx = dt
Substituting these values, we have
I = ∫cos(t).dt
= sin t c …..(2)
Substituting the value of 1 in 2, we have
= sin (x2 – 5) C

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